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For the balanced equation shown below, if 32.8 grams of FeS were reacted with 21.1 grams of HCl, how many grams of H2S would be produced?

FeS+2HCl=>H2S+FeCl2

1.Find limiting reagent

FeS + 2HCl

91g/mol 36.5g/mol

.360=mol .578=mol

.720 .578

2.Figure out the molar mass of H2S

Hx2

Sx1

2+32=34

3.Compare the limiting reagent (2HCl) with H2S and find ratio

2:1

4.Divide ratio of 2HCl and H2S

2 2

1:.5

5.Take ratio (1:.5) and multiply with the limiting reagent MOL and molar mass of H2S

1:.5x.578x34

=9.826

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FeS+2HCl=>H2S+FeCl2

1.Find limiting reagent

FeS + 2HCl

__32.8g____21.1g__91g/mol 36.5g/mol

.360=mol .578=mol

__x 2____x 1__.720 .578

**The limiting reagent is 2HCl**2.Figure out the molar mass of H2S

Hx2

Sx1

2+32=34

3.Compare the limiting reagent (2HCl) with H2S and find ratio

**2**HCl**1**H2S2:1

4.Divide ratio of 2HCl and H2S

__2__:__1__2 2

1:.5

5.Take ratio (1:.5) and multiply with the limiting reagent MOL and molar mass of H2S

1:.5x.578x34

=9.826

Still confused? Click Here to go to the sample problems!