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For the balanced equation shown below, what would be the limiting reagent if 46.3 grams of C2H5NSCl were reacted with 50.5 grams of O2?
2C2H5NSCl+11O2=>4CO2+4H2O+2NO2+2SO3+2HCl
2C2H5NSCl + 11O2
46.3g 50.5g
110.5g/mol 32g/mol
.419=mol 1.57=mol
x 11 x 2
4.609 3.14
The limiting reagent is 11O2
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2C2H5NSCl+11O2=>4CO2+4H2O+2NO2+2SO3+2HCl
2C2H5NSCl + 11O2
46.3g 50.5g
110.5g/mol 32g/mol
.419=mol 1.57=mol
x 11 x 2
4.609 3.14
The limiting reagent is 11O2
Don't understand how to do it? Click Here to look at step by step examples!