:( INCORRECT :(
For the balanced equation shown below, what would be the limiting reagent if 33.2 grams of C2H3O2F were reacted with 27.2 grams of O2?
2C2H3O2F+3O2=>4CO2+2H2O+2HF
2C2H3O2F + 3O2
33.2g 27.2g
78g/mol 32g/mol
.425=mol .85=mol
x 3 x 2
1.275 1.70
The limiting reagent is 2C2H3O2F
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2C2H3O2F+3O2=>4CO2+2H2O+2HF
2C2H3O2F + 3O2
33.2g 27.2g
78g/mol 32g/mol
.425=mol .85=mol
x 3 x 2
1.275 1.70
The limiting reagent is 2C2H3O2F
Don't understand how to do it? Click Here to look at step by step examples!