:( INCORRECT :(
For the balanced equation shown below, what would be the limiting reagent if 70.9 grams of C2H3N were reacted with 192 grams of O2?
4C2H3N+11O2=>8CO+6H2O+4NO2
4C2H3N + 11O2
70.9g 192g
41g/mol 32g/mol
1.72=mol 6=mol
x 11 x4
18.92 24
The limiting reagent is 4C2H3N
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4C2H3N+11O2=>8CO+6H2O+4NO2
4C2H3N + 11O2
70.9g 192g
41g/mol 32g/mol
1.72=mol 6=mol
x 11 x4
18.92 24
The limiting reagent is 4C2H3N
Still confused on how to do it? Click Here to go back to the home page with the examples