:( INCORRECT :(
For the balanced equation shown below, what would be the limiting reagent if 5.60 grams of C7H16 were reacted with 12.4 grams of O2?
C7H16+11O2=>7CO2+8H2OC7H16+11O2
C7H16 + 11O2
5.60g 12.4g
100g/mol 32g/mol
.056=mol .387=mol
x 11 x 1
.616 .387
The limiting reagent is 11O2
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C7H16+11O2=>7CO2+8H2OC7H16+11O2
C7H16 + 11O2
5.60g 12.4g
100g/mol 32g/mol
.056=mol .387=mol
x 11 x 1
.616 .387
The limiting reagent is 11O2
Don't understand how to do it? Click Here to look at step by step examples?