:( INCORRECT :(
For the balanced equation shown below, what would be the limiting reagent if 67.0 grams of Al were reacted with 475 grams of MnO?
2Al+3MnO=>Al2O3+3Mn
2Al + 3MnO
67.0g 475g
27g/mol 71g/mol
2.48=mol 6.69=mol
x 3 x 2
7.44 13.38
The limiting reagent is 2Al
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2Al+3MnO=>Al2O3+3Mn
2Al + 3MnO
67.0g 475g
27g/mol 71g/mol
2.48=mol 6.69=mol
x 3 x 2
7.44 13.38
The limiting reagent is 2Al
Don't understand how to do it? Click Here to look at step by step examples!