## :( INCORRECT :(

For the balanced equation shown below, if 10.4 grams of C3H6 were reacted with 36.0 grams of O2, how many grams of CO would be produced?

C3H6+3O2=3CO+3H2O

1.Find the limiting reagent

C3H6 + 3O2

42g/mol 32g/mol

.247=mol 1.125=mol

.741 1.125

2.Figure out the molar mass of 3CO

Cx1

Ox1

12+16=28

3.Compare the limiting reagent (C3H6) with 3CO and find the ratio

C3H6 3CO

1:3

4.Divide ratio of C3H6 and 3CO

1:3

5.Take ratio (1:3) and multiply with the limiting reagent MOL and molar mass of 3CO

1:3x.247x28

=20.748

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C3H6+3O2=3CO+3H2O

1.Find the limiting reagent

C3H6 + 3O2

__10.4g____36.0g__42g/mol 32g/mol

.247=mol 1.125=mol

__x 3____x 1__.741 1.125

**The limiting reagent is C3H6**2.Figure out the molar mass of 3CO

Cx1

Ox1

12+16=28

3.Compare the limiting reagent (C3H6) with 3CO and find the ratio

C3H6 3CO

1:3

4.Divide ratio of C3H6 and 3CO

1:3

5.Take ratio (1:3) and multiply with the limiting reagent MOL and molar mass of 3CO

1:3x.247x28

=20.748

Still don't understand?

Click Here to look at step by step examples

Click Here to watch a video on how to find the limiting reactant