:( INCORRECT :(
For the balanced equation shown below, what would be the limiting reagent if 17.8 grams of ZnS were reacted with 6.75 grams of O2?
2ZnS+3O2=>2ZnO+2SO2
2ZnS + 3O2
17.8g 6.75g
97g/mol 32g/mol
.183=mol .210=mol
x 3 x 2
.549 .420
The limiting reagent is 3O2
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2ZnS+3O2=>2ZnO+2SO2
2ZnS + 3O2
17.8g 6.75g
97g/mol 32g/mol
.183=mol .210=mol
x 3 x 2
.549 .420
The limiting reagent is 3O2
Don't understand how to do it? Click Here to look at step by step examples!