:( INCORRECT :(
For the balanced equation shown below, what would be the limiting reagent if 60.8 grams of NH3 were reacted with 72.4 grams of O2?
4NH3+5O2=>6H2O+4NO4NH3+5O24NH3+5O2
4NH3 + 5O2
60.8g 72.4g
17g/mol 32g/mol
3.57=mol 2.26=mol
x 5 x 4
17.85 9.04
The limiting reagent is 5O2
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4NH3+5O2=>6H2O+4NO4NH3+5O24NH3+5O2
4NH3 + 5O2
60.8g 72.4g
17g/mol 32g/mol
3.57=mol 2.26=mol
x 5 x 4
17.85 9.04
The limiting reagent is 5O2
Don't understand how to do it? Click Here to look at step by step examples!